Question:
What is the correct sequence of neutrophil formation in cat?
(A) Myelocyte
(B) Myeloblast
(C) Metamyelocyte
(D) Segmented neutrophil
Choose the correct answer from the options given below:
What is the correct sequence of neutrophil formation in cat?
(A) Myelocyte
(B) Myeloblast
(C) Metamyelocyte
(D) Segmented neutrophil
Choose the correct answer from the options given below:
(A) Myelocyte
(B) Myeloblast
(C) Metamyelocyte
(D) Segmented neutrophil
Choose the correct answer from the options given below:
Show Hint
To memorize the sequence of granulopoiesis:
Remember the acronym M-P-M-M-B-S:
Myeloblast \(\rightarrow\) Promyelocyte \(\rightarrow\) Myelocyte \(\rightarrow\) Metamyelocyte \(\rightarrow\) Band \(\rightarrow\) Segmented.
Remember the acronym M-P-M-M-B-S:
Myeloblast \(\rightarrow\) Promyelocyte \(\rightarrow\) Myelocyte \(\rightarrow\) Metamyelocyte \(\rightarrow\) Band \(\rightarrow\) Segmented.
Updated On: Jul 23, 2026
- (A), (B), (C) and (D).
- (D), (C), (A), (B).
- (B), (A), (D) and (C).
- (B), (A), (C) and (D).
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
Granulopoiesis is the process of development and maturation of granulocytes, including neutrophils, in the bone marrow.
During this process, precursor cells undergo distinct morphological changes, including a reduction in cell size, condensation of chromatin, loss of nucleoli, and changes in nuclear shape.
Step 2: Detailed Explanation:
Let us trace the correct chronological stages of neutrophil maturation in the bone marrow:
1. Myeloblast (B): This is the earliest microscopically identifiable precursor in the granulocytic series. It is a large cell with a high nucleus-to-cytoplasm ratio, fine chromatin, and visible nucleoli.
2. Promyelocyte (not listed): The cell develops primary (azurophilic) granules.
3. Myelocyte (A): The cell begins to synthesize secondary (specific) granules. The nucleus becomes round or oval, and chromatin begins to condense.
4. Metamyelocyte (C): In this stage, the nucleus begins to indent or become kidney-bean shaped (the indentation is less than 50% of the nuclear width).
5. Band Neutrophil (not listed): The nuclear indentation becomes deeper, forming a horseshoe or U-shape with a uniform width.
6. Segmented Neutrophil (D): This is the final, mature stage. The nucleus becomes highly condensed and lobulated, with distinct segments connected by thin chromatin filaments. It is released into the bloodstream.
Therefore, the correct developmental sequence is: Myeloblast (B) \(\rightarrow\) Myelocyte (A) \(\rightarrow\) Metamyelocyte (C) \(\rightarrow\) Segmented neutrophil (D).
This corresponds to sequence (B), (A), (C), (D).
Step 3: Final Answer:
The correct option is (D).
Granulopoiesis is the process of development and maturation of granulocytes, including neutrophils, in the bone marrow.
During this process, precursor cells undergo distinct morphological changes, including a reduction in cell size, condensation of chromatin, loss of nucleoli, and changes in nuclear shape.
Step 2: Detailed Explanation:
Let us trace the correct chronological stages of neutrophil maturation in the bone marrow:
1. Myeloblast (B): This is the earliest microscopically identifiable precursor in the granulocytic series. It is a large cell with a high nucleus-to-cytoplasm ratio, fine chromatin, and visible nucleoli.
2. Promyelocyte (not listed): The cell develops primary (azurophilic) granules.
3. Myelocyte (A): The cell begins to synthesize secondary (specific) granules. The nucleus becomes round or oval, and chromatin begins to condense.
4. Metamyelocyte (C): In this stage, the nucleus begins to indent or become kidney-bean shaped (the indentation is less than 50% of the nuclear width).
5. Band Neutrophil (not listed): The nuclear indentation becomes deeper, forming a horseshoe or U-shape with a uniform width.
6. Segmented Neutrophil (D): This is the final, mature stage. The nucleus becomes highly condensed and lobulated, with distinct segments connected by thin chromatin filaments. It is released into the bloodstream.
Therefore, the correct developmental sequence is: Myeloblast (B) \(\rightarrow\) Myelocyte (A) \(\rightarrow\) Metamyelocyte (C) \(\rightarrow\) Segmented neutrophil (D).
This corresponds to sequence (B), (A), (C), (D).
Step 3: Final Answer:
The correct option is (D).
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