Question:
What is the basic chromosome number is present in C genome of Brassica oleracea ?
What is the basic chromosome number is present in C genome of Brassica oleracea ?
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Remember U's Triangle basic numbers with the sequential acronym: 'A-B-C' corresponds to $x = 10, 8, 9$ (where $10$ is *B. rapa*, $8$ is *B. nigra*, and $9$ is *B. oleracea*).
Updated On: Jul 23, 2026
- x = 18
- x = 9
- x = 36
- x = 16
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
The evolutionary and cytogenetic relationships among different *Brassica* species are explained by the classical U's Triangle model (developed by Woo Jang-choon in 1935).
This model describes three basic diploid species and their three amphidiploid hybrids.
Step 2: Detailed Explanation:
According to U's Triangle, the three primary diploid *Brassica* species are:
1. Brassica nigra (A genome, $x = 8$, $2n = 16$)
2. Brassica oleracea (C genome, $x = 9$, $2n = 18$)
3. Brassica rapa (B genome, $x = 10$, $2n = 20$)
The basic chromosome number ($x$) represents the single set of chromosomes found in the haploid gametes of the diploid species.
For Brassica oleracea (which includes cabbage, cauliflower, broccoli, and Brussels sprouts), the C genome has a basic chromosome number of $x = 9$.
Since it is a diploid species, its somatic cells contain two sets of these chromosomes, giving a total of:
\[ 2n = 2x = 18 \text{ chromosomes} \]
Therefore, the basic chromosome number in the C genome of Brassica oleracea is 9.
Step 3: Final Answer:
The basic chromosome number is $x = 9$, corresponding to option (B).
The evolutionary and cytogenetic relationships among different *Brassica* species are explained by the classical U's Triangle model (developed by Woo Jang-choon in 1935).
This model describes three basic diploid species and their three amphidiploid hybrids.
Step 2: Detailed Explanation:
According to U's Triangle, the three primary diploid *Brassica* species are:
1. Brassica nigra (A genome, $x = 8$, $2n = 16$)
2. Brassica oleracea (C genome, $x = 9$, $2n = 18$)
3. Brassica rapa (B genome, $x = 10$, $2n = 20$)
The basic chromosome number ($x$) represents the single set of chromosomes found in the haploid gametes of the diploid species.
For Brassica oleracea (which includes cabbage, cauliflower, broccoli, and Brussels sprouts), the C genome has a basic chromosome number of $x = 9$.
Since it is a diploid species, its somatic cells contain two sets of these chromosomes, giving a total of:
\[ 2n = 2x = 18 \text{ chromosomes} \]
Therefore, the basic chromosome number in the C genome of Brassica oleracea is 9.
Step 3: Final Answer:
The basic chromosome number is $x = 9$, corresponding to option (B).
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