Question:
What is the average oxidation number of carbon in carbon suboxide \(\mathrm{C}_3 \mathrm{O}_2\) ?
What is the average oxidation number of carbon in carbon suboxide \(\mathrm{C}_3 \mathrm{O}_2\) ?
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Set the sum of oxidation numbers to zero, with oxygen as minus two.
Updated On: Nov 13, 2026
0
\(+\frac{1}{3}\)
\(+\frac{4}{3}\)
+2
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
In a neutral molecule the sum of oxidation numbers is zero. Oxygen is \(-2\).
Step 2: Calculation
Let the average oxidation number of C be \(x\).
\(3x + 2(-2) = 0\)
\(3x = 4\), so \(x = +\dfrac{4}{3}\).
Step 3: Compare the options
The value \(+\dfrac{4}{3}\) is in the options.
Final Answer:
The average oxidation number of carbon is plus four-thirds. \[ \boxed{\text{(C) }+\dfrac{4}{3}} \]
In a neutral molecule the sum of oxidation numbers is zero. Oxygen is \(-2\).
Step 2: Calculation
Let the average oxidation number of C be \(x\).
\(3x + 2(-2) = 0\)
\(3x = 4\), so \(x = +\dfrac{4}{3}\).
Step 3: Compare the options
The value \(+\dfrac{4}{3}\) is in the options.
Final Answer:
The average oxidation number of carbon is plus four-thirds. \[ \boxed{\text{(C) }+\dfrac{4}{3}} \]
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