Question

What is molecular formula of allyl bromide?

• A. \( \mathrm{C_2H_4Br} \)
• B. \( \mathrm{C_2H_3Br} \)
• C. \( \mathrm{C_3H_5Br} \)
• D. \( \mathrm{C_3H_6Br} \)

Hint:

Allyl compounds contain the \(\mathrm{CH_2=CH-CH_2-}\) structural unit.

Answer 1

The Correct Option is C

Step 1: Understanding allyl group.
The allyl group has the structure \( \mathrm{CH_2=CH-CH_2-} \).

Step 2: Formation of allyl bromide.
When bromine replaces one hydrogen atom of the allyl group, allyl bromide is formed.

Step 3: Counting atoms.
Carbon atoms = 3, Hydrogen atoms = 5, Bromine atom = 1.

Step 4: Conclusion.
Thus, the molecular formula of allyl bromide is \( \mathrm{C_3H_5Br} \).