Question:
What is molecular formula of allyl bromide?
What is molecular formula of allyl bromide?
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Allyl compounds contain the \(\mathrm{CH_2=CH-CH_2-}\) structural unit.
Updated On: Feb 11, 2026
- \( \mathrm{C_2H_4Br} \)
- \( \mathrm{C_2H_3Br} \)
- \( \mathrm{C_3H_5Br} \)
- \( \mathrm{C_3H_6Br} \)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding allyl group.
The allyl group has the structure \( \mathrm{CH_2=CH-CH_2-} \).
Step 2: Formation of allyl bromide.
When bromine replaces one hydrogen atom of the allyl group, allyl bromide is formed.
Step 3: Counting atoms.
Carbon atoms = 3, Hydrogen atoms = 5, Bromine atom = 1.
Step 4: Conclusion.
Thus, the molecular formula of allyl bromide is \( \mathrm{C_3H_5Br} \).
The allyl group has the structure \( \mathrm{CH_2=CH-CH_2-} \).
Step 2: Formation of allyl bromide.
When bromine replaces one hydrogen atom of the allyl group, allyl bromide is formed.
Step 3: Counting atoms.
Carbon atoms = 3, Hydrogen atoms = 5, Bromine atom = 1.
Step 4: Conclusion.
Thus, the molecular formula of allyl bromide is \( \mathrm{C_3H_5Br} \).
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