Concept:
This is a letter arrangement analogy.
We must find the same rearrangement pattern used in
\[
\text{PALE}\rightarrow \text{LEAP}
\]
and apply it to get
\[
\text{SHOP}
\]
Step 1: Observe the first pair.
The word
\[
\text{PALE}
\]
has letters in positions:
\[
1=P,\quad 2=A,\quad 3=L,\quad 4=E
\]
The word
\[
\text{LEAP}
\]
is formed as
\[
3^{rd},\ 4^{th},\ 2^{nd},\ 1^{st}
\]
because
\[
L,\ E,\ A,\ P
\]
Step 2: Apply reverse pattern.
We need a word whose rearrangement in the order
\[
3,\ 4,\ 2,\ 1
\]
gives
\[
\text{SHOP}
\]
Let the missing word be
\[
abcd
\]
Then according to the pattern,
\[
cdba=\text{SHOP}
\]
So,
\[
c=S,\quad d=H,\quad b=O,\quad a=P
\]
Therefore,
\[
abcd=\text{POSH}
\]
Step 3: Verify.
Apply the same pattern to POSH:
\[
P=1,\quad O=2,\quad S=3,\quad H=4
\]
Taking \(3,4,2,1\), we get
\[
S,\ H,\ O,\ P
\]
\[
=\text{SHOP}
\]
Step 4: Final answer.
\[
\boxed{\text{POSH}}
\]