Step 1: Understanding the Concept
In a cyclic alcohol the carbon bearing OH is C-1 and the compound is named as a cycloalkanol.
Step 2: Read the Structure
The ring is cyclobutane with OH on one carbon. The carbon next to it carries an ethyl group, and the carbon on the other side of the OH carbon carries a methyl group.
Step 3: Number the Ring
C-1 has OH, the ethyl-bearing neighbour is C-2, and the methyl-bearing neighbour on the other side is C-4. The locant set is {2, 4} either way, so the substituent that comes first alphabetically (ethyl) gets the lower number.
Step 4: Name
2-Ethyl-4-methylcyclobutanol, which is option (C).
Final Answer:
The compound is 2-ethyl-4-methylcyclobutanol.
\[ \boxed{\text{(C) }\text{2-Ethyl-4-methyl cyclobutanol}} \]