Question

What is bond order in \(\text{N}_{2}\) molecule?

• A. \(1\)
• B. \(2\)
• C. \(3\)
• D. \(4\)

Hint:

Count bonding and antibonding electrons in the MO configuration of N2 and use half the difference.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
Bond order \(=\frac{N_b-N_a}{2}\), where \(N_b\) and \(N_a\) are the electrons in bonding and antibonding molecular orbitals.

Step 2: MO configuration of N2
\(\text{N}_{2}\) has 14 electrons.
\(\sigma 1s^2\,\sigma^{*}1s^2\,\sigma 2s^2\,\sigma^{*}2s^2\,\pi 2p_x^2=\pi 2p_y^2\,\sigma 2p_z^2\).
So \(N_b=10\) and \(N_a=4\).

Step 3: Calculation
Bond order \(=\frac{10-4}{2}=3\), option (C).

Final Answer:
The bond order of N2 is 3. \[ \boxed{\text{(C) }3} \]