Step 1: Identify the salt
CuSO\(_4\) comes from the weak base Cu(OH)\(_2\) and the strong acid H\(_2\)SO\(_4\).
Step 2: Hydrolysis
Only the cation hydrolyses: \(\text{Cu}^{2+}+2\text{H}_2\text{O}\rightleftharpoons\text{Cu(OH)}_2+2\text{H}^+\).
This releases H\(^+\), so pH \(<7\).
Step 3: Check options
(A) is false, since the anion SO\(_4^{2-}\) does not react (it is the conjugate base of a strong acid).
(B) is false, an acidic solution turns blue litmus red.
(C) is true.
(D) is false, since the salt does hydrolyse.
Final Answer:
CuSO\(_4\) solution has pH below \(7\), option (C).
\[ \boxed{\text{(C)}} \]