Step 1: Understanding the Question:
Argon has atomic number 18, so a neutral atom has 18 electrons. We must count all electrons sitting in s subshells and all electrons sitting in p subshells.
Step 2: Write the electronic configuration:
\[ 1s^2\,2s^2\,2p^6\,3s^2\,3p^6 \]
Step 3: Count the s electrons:
The s subshells are 1s, 2s and 3s. Each holds 2 electrons, so the total is \(2+2+2 = 6\).
Step 4: Count the p electrons:
The p subshells are 2p and 3p. They hold \(6 + 6 = 12\) electrons.
Step 5: Check the total:
\(6 + 12 = 18\), which equals the number of electrons in argon. Option A (12 and 6) swaps the two counts. B and D do not add up to 18 in a meaningful way and miss the filled 2p and 3p subshells.
Final Answer:
Argon has 6 electrons in s orbitals and 12 in p orbitals.
\[ \boxed{\text{(C) }6\ \text{and}\ 12} \]