Question:
What are the respective oxidation states of sulphur atoms numbered 1 to 4 in tetrathionate ion as shown below?
What are the respective oxidation states of sulphur atoms numbered 1 to 4 in tetrathionate ion as shown below?
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Sulphur bonded to oxygen â high oxidation state; SâS bonded sulphur â lower or zero oxidation state.
Updated On: Apr 26, 2026
- \(0, +5, +5, 0\)
- \(+5, 0, 0, +5\)
- \(+2, 0, 0, +2\)
- \(+2, -1, -1, +2\)
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The Correct Option is B
Solution and Explanation
Concept:
In tetrathionate ion \((\text{S}_4\text{O}_6^{2-})\), oxidation states depend on bonding:
Step 2: Identify middle sulphur atoms (2 and 3). These sulphur atoms are bonded only to sulphur atoms. Thus their oxidation state: \[ 0 \]
Step 3: Conclusion. \[ (+5, 0, 0, +5) \]
In tetrathionate ion \((\text{S}_4\text{O}_6^{2-})\), oxidation states depend on bonding:
- Sulphur bonded to oxygen â higher oxidation state
- Sulphur bonded only to sulphur â lower oxidation state
Step 2: Identify middle sulphur atoms (2 and 3). These sulphur atoms are bonded only to sulphur atoms. Thus their oxidation state: \[ 0 \]
Step 3: Conclusion. \[ (+5, 0, 0, +5) \]
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