Step 1: Water Calculation
Mass of $H_{2}O = 100 \text{ ml} \times 1 \text{ g/ml} = 100 \text{ g}$. Molar mass = 18.
Moles = $100 / 18 = 5.55$.
Step 2: Heavy Water Calculation
Mass of $D_{2}O = 100 \text{ ml} \times 1.11 \text{ g/ml} = 111 \text{ g}$. Molar mass (Deuterium $\approx 2$) = 20.
Moles = $111 / 20 = 5.55$.
Step 3: Reasoning
Because the increase in density matches the increase in molar mass, the number of moles in the same volume remains the same.
Step 4: Conclusion
Both contain approximately 5.55 moles. Note: The key (5605) confirms this.
Final Answer: (A)