Question

Volume of 3%solution of sodium carbonate necessary to neutralise a litre of 0.1 N sulphuric acid is

• A. 176.66 ml
• B. 156.6 ml
• C. 116.0 ml
• D. 196.1 ml

Hint:

To calculate the volume required for neutralization, use the relation \( N_1 V_1 = N_2 V_2 \), where \( N_1 \) and \( V_1 \) are the normality and volume of one reactant, and \( N_2 \) and \( V_2 \) are those of the other.

Answer 1

The Correct Option is A

Step 1: Use the neutralization equation.
The neutralization reaction between sodium carbonate and sulphuric acid is given by: \[ \text{Na}_2 \text{CO}_3 + \text{H}_2 \text{SO}_4 \rightarrow \text{Na}_2 \text{SO}_4 + \text{CO}_2 + \text{H}_2 \text{O} \] The molar equivalents of sodium carbonate are equal to those of sulphuric acid. Using the normality and volume of sulphuric acid, calculate the volume of sodium carbonate solution required.
Step 2: Calculate the volume.
The required volume of sodium carbonate solution is calculated as 176.66 ml using the equivalence factor. Final Answer: \[ \boxed{176.66 \, \text{ml}} \]