Question:

Volume of 3%solution of sodium carbonate necessary to neutralise a litre of 0.1 N sulphuric acid is

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Use the equivalence factor and the molarity of the acid and base to calculate the volume needed for neutralization.
Updated On: Mar 25, 2026
  • 176.66 ml
  • 156.6 ml
  • 116.0 ml
  • 196.1 ml
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The Correct Option is A

Solution and Explanation


Step 1: Use the neutralization equation.

The neutralization of sulfuric acid and sodium carbonate can be represented by \( \text{H}_2 \text{SO}_4 + \text{Na}_2 \text{CO}_3 \rightarrow \text{Na}_2 \text{SO}_4 + \text{CO}_2 + \text{H}_2 \text{O} \).
Step 2: Conclusion.

The required volume is 176.66 ml based on the equivalent amounts of acid and base. Final Answer: \[ \boxed{176.66 \, \text{ml}} \]
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