Question:

Vectors \(a\hat{i}+b\hat{j}+\hat{k}\) and \(2\hat{i}-3\hat{j}+4\hat{k}\) are perpendicular to each other when \(3a+2b = 7\), the ratio of a to b is \(x/2\). The value of x is

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Perpendicular vectors have zero dot product; solve the two equations for a and b.
Updated On: Oct 1, 2026
  • \(4\)
  • \(1\)
  • \(8\)
  • \(3\)
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The Correct Option is B

Solution and Explanation

Step 1: Use the dot product
For perpendicular vectors, \((a\hat i + b\hat j + \hat k)\cdot(2\hat i - 3\hat j + 4\hat k) = 0\), so \(2a - 3b + 4 = 0\).

Step 2: Use the given relation
We also have \(3a + 2b = 7\). From the first, \(a = \frac{3b-4}{2}\).

Step 3: Solve
\(3\cdot\frac{3b-4}{2} + 2b = 7\) gives \(9b - 12 + 4b = 14\), so \(b = 2\) and \(a = 1\).

Step 4: Find x
\(\frac ab = \frac12 = \frac x2\), so \(x = 1\). Option (B).

Final Answer:
The value of x is 1. \[ \boxed{\text{(B)}\ 1} \]
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