Question:

Unpolarized light of intensity \(I_0\) is incident on surface of a block of glass at Brewster's angle. In that case, which one of the following statements is true ?

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At Brewster's angle the reflected beam is completely plane polarized, but only a fraction (less than half) of the incident intensity is reflected.
Updated On: Nov 11, 2026
  • transmitted light is partially polarized with intensity \(I_0/2\).
  • transmitted light is completely polarized with intensity less than \(I_0/2\).
  • reflected light is completely polarized with intensity less than \(I_0/2\).
  • reflected light is partially polarized with intensity \(I_0/2\).
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The Correct Option is C

Solution and Explanation

At the Brewster angle \(\tan i_p = \mu\), the reflected and refracted rays are perpendicular, and the reflected light is completely plane polarized (vibrations perpendicular to the plane of incidence).
Unpolarized light can be split into two equal components of \(I_0/2\) each (parallel and perpendicular to the plane of incidence). The parallel component is not reflected at all; only part of the perpendicular component (about 15 percent for glass) is reflected.
So the reflected intensity is less than \(I_0/2\), and the transmitted light is partially polarized with intensity greater than \(I_0/2\).
Thus statement (3) is true.
Answer: (3) reflected light is completely polarized with intensity less than \(I_0/2\)
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