Question:

Two wires are made of the same material and have the same volume. However wire 1 has cross-sectional area A and wire 2 has cross-sectional area 3A. If the length of wire 1 increases by Δ x on applying force F, how much force is needed to stretch wire 2 by the same amount?

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For same material, extension depends on (FL)/(A).
Updated On: Mar 20, 2026
  • \(4F\)
  • \(6F\)
  • \(9F\)
  • F
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The Correct Option is C

Solution and Explanation


Step 1:
Extension of a wire: Δ x = (FL)/(AY)
Step 2:
Same volume implies: A₁L₁ = A₂L₂ ⟹ L₂ = (L₁)/(3)
Step 3:
For same extension: (F₁L₁)/(A₁Y) = (F₂L₂)/(A₂Y) ⟹ F₂ = 9F₁
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