Question:
Two waves of wavelengths 99 cm and 100 cm both travelling with velocity 396 m/s are made to interfere. The number of beats produced by them is
Two waves of wavelengths 99 cm and 100 cm both travelling with velocity 396 m/s are made to interfere. The number of beats produced by them is
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The beat frequency is the difference in the frequencies of the two interfering waves.
Updated On: Mar 24, 2026
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The Correct Option is C
Solution and Explanation
Step 1: Find the beat frequency.
The beat frequency is given by the difference in frequencies of the two waves. Frequency is \( f = \frac{v}{\lambda} \), where \( v \) is the velocity and \( \lambda \) is the wavelength.
Step 2: Calculate the frequencies of the two waves.
For the first wave, \( f_1 = \frac{396}{0.99} = 400 \, \text{Hz} \) and for the second wave, \( f_2 = \frac{396}{1.00} = 396 \, \text{Hz} \).
Step 3: Find the beat frequency.
The beat frequency is \( |f_1 - f_2| = 400 - 396 = 4 \, \text{Hz} \). Final Answer: \[ \boxed{4} \]
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