
For multiple reflections, calculate distances iteratively for each reflection
Step 1: Calculate the positions of images formed by multiple reflections - The distance of the first image from mirror A is \[ 2 \, \text{cm}. \] The distance of the first image from mirror B is \[ 10 + 2 = 12 \, \text{cm}. \] The distance of the second image from mirror A is \[ 10 + 12 = 22 \, \text{cm}. \] The distance of the second nearest image behind mirror A is \[ 18 \, \text{cm}. \]
Final Answer: The distance of the second nearest image is 18 cm.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)