Question:

Two substances R and S decompose in solution independently, both following first order kinetics. The rate constant of R is twice that of S. Initially 0.5 millimoles of R and 0.25 of S. The molarities of R and S will be equal at the end of time equal to:

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For first order reactions, half-life is independent of initial concentration.
Updated On: Mar 24, 2026
  • twice the half-life of R
  • twice the half-life of S
  • the half-life of S
  • the half-life of R
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The Correct Option is D

Solution and Explanation


Step 1:
First order decay: \[ [R]=R_0 e^{-k_R t},\quad [S]=S_0 e^{-k_S t} \]
Step 2:
Given \(k_R=2k_S\) and \(R_0=2S_0\).
Step 3:
Equality occurs when: \[ t = \frac{\ln 2}{k_R} = t_{1/2}(R) \]
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