Question:

Two sources of sound are emitting progressive waves \(y_1 = 4sin708\,πt\) and \(y_2 = 3sin700\,πt\). The sources are placed close to each other. The number of beats heard per second and intensity ratio between waxing and wanning are respectively

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Frequencies come from the angular frequencies, and intensity goes as amplitude squared.
Updated On: Oct 1, 2026
  • \(4\) , \(16:9\)
  • \(8\) , \(16:9\)
  • \(8\) , \(49:1\)
  • \(4\) , \(49:1\)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
For \(y = A\sin\omega t\), the frequency is \(f = \frac{\omega}{2\pi}\). Beats per second equal the difference in frequency. Intensity is proportional to the square of the amplitude.

Step 2: Key Formula or Approach:
Maximum amplitude \(= A_1 + A_2\) and minimum amplitude \(= A_1 - A_2\).

Step 3: Detailed Explanation:
\(f_1 = \frac{708\pi}{2\pi} = 354\) Hz and \(f_2 = \frac{700\pi}{2\pi} = 350\) Hz.
Beats per second \(= 354 - 350 = 4\).
\[ \frac{I_{max}}{I_{min}} = \frac{(4 + 3)^2}{(4 - 3)^2} = \frac{49}{1} \]
The ratio \(16:9\) is the ratio of the intensities of the two sources, not of the maximum and minimum intensity.

Final Answer:
There are \(4\) beats per second and the intensity ratio is \(49:1\), option (D). \[ \boxed{4,\ 49:1} \]
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