Step 1: Open pipe:
Let the open pipe have fundamental \(f_0 = \frac{v}{2L}\). Its first overtone is the second harmonic, \(2f_0\).
Step 2: Closed pipe of the same length:
Closing one end gives a fundamental of \(\frac{v}{4L} = \frac{f_0}{2}\). A closed pipe has only odd harmonics, so its second overtone is the fifth harmonic: \(5\times\frac{f_0}{2} = 2.5f_0\).
Step 3: Difference:
\[ 2.5f_0 - 2f_0 = 0.5f_0 = 100\text{ Hz} \Rightarrow f_0 = 200\text{ Hz} \]
Final Answer:
The fundamental frequency of the open pipe is 200 Hz, option (A).
\[ \boxed{200\text{ Hz}} \]