Question:
Two satellites \(A\) and \(B\) of same mass are revolving round the earth at height \(2R\) and \(3R\) respectively above the surface of the earth. The ratio of kinetic energies of \(A\) to \(B\) will be
Two satellites \(A\) and \(B\) of same mass are revolving round the earth at height \(2R\) and \(3R\) respectively above the surface of the earth. The ratio of kinetic energies of \(A\) to \(B\) will be
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Kinetic energy of a satellite in circular orbit is inversely proportional to orbital radius.
Updated On: Feb 18, 2026
- \(3:2\)
- \(3:4\)
- \(2:3\)
- \(4:3\)
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The Correct Option is D
Solution and Explanation
Step 1: Expression for kinetic energy of satellite.
For a satellite in circular orbit, \[ K = \frac{GMm}{2r}. \]
Step 2: Orbital radii.
\[ r_A = R + 2R = 3R, \quad r_B = R + 3R = 4R. \]
Step 3: Ratio of kinetic energies.
\[ \frac{K_A}{K_B} = \frac{r_B}{r_A} = \frac{4R}{3R} = \frac{4}{3}. \]
Step 4: Conclusion.
The ratio of kinetic energies is \(4:3\).
For a satellite in circular orbit, \[ K = \frac{GMm}{2r}. \]
Step 2: Orbital radii.
\[ r_A = R + 2R = 3R, \quad r_B = R + 3R = 4R. \]
Step 3: Ratio of kinetic energies.
\[ \frac{K_A}{K_B} = \frac{r_B}{r_A} = \frac{4R}{3R} = \frac{4}{3}. \]
Step 4: Conclusion.
The ratio of kinetic energies is \(4:3\).
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