Question:
Two satellites, A and B, have masses m and 2m respectively. A is in a circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, \(T_A/T_B\), is ;
Two satellites, A and B, have masses m and 2m respectively. A is in a circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, \(T_A/T_B\), is ;
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For a circular orbit, \(\frac{mv^2}{r}=\frac{GMm}{r^2}\), so kinetic energy \(T=\frac{GMm}{2r}\).
Updated On: Nov 5, 2026
- 2
- \(\frac{1}{2}\)
- \(\sqrt{\frac{1}{2}}\)
- 1
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The Correct Option is D
Solution and Explanation
Orbital speed: \(v^2=\frac{GM}{r}\), so \(T=\frac12mv^2=\frac{GMm}{2r}\).
\(T_A=\frac{GMm}{2R}\) and \(T_B=\frac{GM(2m)}{2(2R)}=\frac{GMm}{2R}\).
\(\frac{T_A}{T_B}=1\).
Answer: (4) 1
\(T_A=\frac{GMm}{2R}\) and \(T_B=\frac{GM(2m)}{2(2R)}=\frac{GMm}{2R}\).
\(\frac{T_A}{T_B}=1\).
Answer: (4) 1
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