Two projectiles P1 and P2 thrown with speed in the ratio \( \sqrt3 \) : \( \sqrt2 \), attain the same height during their motion. If P2 is thrown at an angle of 60\( ^\circ \) with the horizontal, the angle of projection of P1 with horizontal will be :
Two projectiles P1 and P2 thrown with speed in the ratio \( \sqrt3 \) : \( \sqrt2 \), attain the same height during their motion. If P2 is thrown at an angle of 60\( ^\circ \) with the horizontal, the angle of projection of P1 with horizontal will be :
Show Hint
- 15\( ^\circ \)
- 30\( ^\circ \)
- 45\( ^\circ \)
- 60\( ^\circ \)
The Correct Option is C
Solution and Explanation
Step 2: \( \frac{u_1^2}{u_2^2}=\frac32 \) and \( \theta_2=60^\circ \Rightarrow\sin^2\theta_2=\frac34 \).
Step 3: \( \sin^2\theta_1=\frac{u_2^2}{u_1^2}\sin^2\theta_2=\frac23\cdot\frac34=\frac12 \).
Step 4: \( \sin\theta_1=\frac1{\sqrt2}\Rightarrow\theta_1=45^\circ \).
Answer: (C) 45\(^\circ\)
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