Step 1: Understanding the Question:
Two identical positive ions experience an electrostatic repulsive force due to their charges. The positive charge arises because electrons are missing. We need to find the number of missing electrons ($n$) in terms of force, distance, and fundamental constants.
Step 2: Key Formula or Approach:
According to Coulomb's Law, the electrostatic force $F$ between two point charges separated by a distance $d$ in a vacuum is:
$$F = \frac{1}{4\pi\varepsilon_0}\frac{q_1 q_2}{d^2}$$
Since both ions carry the same charge $q_1 = q_2 = q$:
$$F = \frac{1}{4\pi\varepsilon_0}\frac{q^2}{d^2}$$
By the quantization of charge, the net positive charge on an ion missing $n$ electrons is:
$$q = ne$$
Step 3: Detailed Explanation:
Substitute $q = ne$ into Coulomb's law equation:
$$F = \frac{1}{4\pi\varepsilon_0}\frac{(ne)^2}{d^2}$$
$$F = \frac{1}{4\pi\varepsilon_0}\frac{n^2 e^2}{d^2}$$
To isolate $n^2$, multiply both sides by $4\pi\varepsilon_0 d^2$ and divide by $e^2$:
$$n^2 = \frac{4\pi\varepsilon_0 F d^2}{e^2}$$
Take the square root of both sides to solve for the number of electrons $n$:
$$n = \sqrt{\frac{4\pi\varepsilon_0 F d^2}{e^2}}$$
Step 4: Final Answer:
The expression for the number of missing electrons is $\sqrt{\frac{4\pi\varepsilon_0 Fd^2}{e^2}}$, which matches option (D).