Two particles of charges $+e$ and $+2e$ are at 16 cm away from each other. Where should another charge q be placed between them, so that the system remains in equilibrium?
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For equilibrium, the forces on the middle charge from both ends must balance.
Step 1: For equilibrium, force on q due to both charges must be equal and opposite. Step 2: $\frack e qx² = \frack (2e) q(16-x)² → \frac1x² = \frac2(16-x)² → \frac16-xx = \sqrt2 → x = \frac161+\sqrt2 = 6.63$ cm. Step 3: Final Answer: 6.63 cm from $+e$.