Question:

Two particles of charges $+e$ and $+2e$ are at 16 cm away from each other. Where should another charge q be placed between them, so that the system remains in equilibrium?

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For equilibrium, the forces on the middle charge from both ends must balance.
Updated On: Apr 16, 2026
  • 24 cm from $+e$
  • 12.23 cm from $+e$
  • 80 cm from $+e$
  • 6.63 cm from $+e$
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The Correct Option is D

Solution and Explanation


Step 1:
For equilibrium, force on q due to both charges must be equal and opposite.

Step 2:
$\frack e qx² = \frack (2e) q(16-x)² → \frac1x² = \frac2(16-x)² → \frac16-xx = \sqrt2 → x = \frac161+\sqrt2 = 6.63$ cm.

Step 3:
Final Answer: 6.63 cm from $+e$.
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