Question:

Two particles A and B are moving along positive x- and positive y-axes respectively with the same speed v m s$^{-1}$. At t = 0, they both pass through the origin. The equation of the straight line joining A and B at time t is:

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When two particles move along perpendicular axes with equal speed, their positions form a straight line with slope -1.
Updated On: Jul 18, 2026
  • \(y(t) = x(t) + vt\)
  • \(y(t) = -x(t) + vt\)
  • \(y(t) = x(t)\)
  • \(y(t) = -x(t)\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding motion of particle A.
Particle A moves along positive x-axis with speed \(v\), so: \[ x_A = vt, \quad y_A = 0 \]

Step 2: Understanding motion of particle B.
Particle B moves along positive y-axis with speed \(v\), so: \[ x_B = 0, \quad y_B = vt \]

Step 3: Coordinates of both particles at time t.
So at time \(t\): \[ A(vt, 0), \quad B(0, vt) \]

Step 4: Equation of line joining two points.
Slope of AB: \[ m = \frac{vt - 0}{0 - vt} = -1 \] Using point A: \[ y - 0 = -1(x - vt) \]

Step 5: Simplification.
\[ y = -x + vt \]

Step 6: Final conclusion.
Hence, equation of line is: \[ \boxed{y = -x + vt} \]
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