Question:
Two parallel plate air capacitors of same capacity ' C ' are connected in parallel to a battery of e.m.f. ' $E$ '. Then one of the capacitors is completely filled with dielectric material of constant ' K '. The change in the effective capacity of the parallel combination is
Two parallel plate air capacitors of same capacity ' C ' are connected in parallel to a battery of e.m.f. ' $E$ '. Then one of the capacitors is completely filled with dielectric material of constant ' K '. The change in the effective capacity of the parallel combination is
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Effective capacity in parallel is simply the sum of individual capacities.
Updated On: May 12, 2026
- $\frac{\text{C}}{(\text{K}-1)}$
- $\frac{\text{KC}}{\text{K}-1}$
- $\text{KC} + 1$
- $\text{C}(\text{K} - 1)$
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Parallel combination capacity is $C_{eq} = C_1 + C_2$. Inserting dielectric changes $C$ to $KC$.
Step 2: Meaning
Initial capacity $C_{i} = C + C = 2C$.
Step 3: Analysis
Final capacity after filling one: $C_{f} = KC + C = C(K + 1)$.
Change in capacity $\Delta C = C_{f} - C_{i} = C(K + 1) - 2C = CK + C - 2C$.
Step 4: Conclusion
$\Delta C = CK - C = C(K - 1)$. Final Answer: (D)
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