Two long parallel conductors \(S_1\) and \(S_2\) are separated by a distance \(10\) cm and carrying currents of \(4\) A and \(2\) A respectively. The conductors are placed along x-axis in X–Y plane. There is a point P located between the conductors (as shown in figure). A charge particle of \(3π\) coulomb is passing through the point P with velocity \(\overrightarrow v=(2\hat i+3\hat j)\) m/s; where \(\hat i\) and \(\hat j\) represents unit vector along x & y axis respectively. The force acting on the charge particle is \(4π×10^{−5}(−x\hat i+2\hat j)N\). The value of x is:
Field at P is
=\(\bigg(\frac{µ_0×i_1}{2πr_1}–\frac{µ_0i_2}{2πr_2}\bigg)\bigg(−\hat k\bigg)\)
=\(−\bigg(\frac{µ_04}{2π×0.04}−\frac{µ_0×2}{2π×0.06}\bigg)\hat k=–\frac{µ_0×200}{6π}\hat k\)
Therefore, the force
\(\overrightarrow F=\overrightarrow {qv} ×\overrightarrow B\)
= \(3π(2\hat i+3\hat j)×\bigg(−\bigg(\frac{µ_0×200}{6π}\bigg)\hat k\bigg)\)
=\(3π\bigg(\frac{200µ_0}{3π\hat j}−\frac{100µ_0}{π}\hat i)\)
= \(200µ_0\hat j–300µ_0\hat i\)
= \(4π×10^{−5}(2\hat j–3\hat i)\)
\(Hence,\) \(x = 3\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Semiconductors are a crystalline solid materials, whose electrical conductivity lies between a conductor and an insulator. Semiconductors are mainly used in the manufacturing of electronic devices like capacitors, transistors, diodes, Integrated circuits, etc.