Question:
Two lines
L₁:x=5, (y)/(3-α)=(z)/(-2)
L₂:x=α, (y)/(-1)=(z)/(2-α)
are coplanar. Then α can take value(s)
Two lines
L₁:x=5, (y)/(3-α)=(z)/(-2)
L₂:x=α, (y)/(-1)=(z)/(2-α)
are coplanar. Then α can take value(s)
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Two lines are coplanar if the scalar triple product is zero.
Updated On: Mar 20, 2026
- \(1,4,5\)
- \(1,2,5\)
- \(3,4,5\)
- 2,4,5
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The Correct Option is B
Solution and Explanation
Using the coplanarity condition of two lines and solving the determinant, we get
α=1,2,5
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