Question:
Two light waves amplitudes in the ratio \(3:1\) produce interference. The ratio of the maximum to minimum intensity is
Two light waves amplitudes in the ratio \(3:1\) produce interference. The ratio of the maximum to minimum intensity is
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Intensity ratio is $\frac{(a_1+a_2)^2}{(a_1-a_2)^2}$.
Updated On: Oct 1, 2026
- \(9:4\)
- \(16:9\)
- \(3:2\)
- \(4:1\)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Write the formula
\(\frac{I_{max}}{I_{min}}=\frac{(a_1+a_2)^2}{(a_1-a_2)^2}\).
Step 2: Substitute
With \(a_1:a_2=3:1\): \(\frac{(3+1)^2}{(3-1)^2}=\frac{16}{4}=4:1\). Option (D).
Final Answer:
The ratio is \(4:1\), option (D). \[ \boxed{\text{(D) }4:1} \]
\(\frac{I_{max}}{I_{min}}=\frac{(a_1+a_2)^2}{(a_1-a_2)^2}\).
Step 2: Substitute
With \(a_1:a_2=3:1\): \(\frac{(3+1)^2}{(3-1)^2}=\frac{16}{4}=4:1\). Option (D).
Final Answer:
The ratio is \(4:1\), option (D). \[ \boxed{\text{(D) }4:1} \]
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