Question:
Two identical strings X and Z made of same material have tension \(T_X\) and \(T_Z\) in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio \(T_X/T_Z\) is
Two identical strings X and Z made of same material have tension \(T_X\) and \(T_Z\) in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio \(T_X/T_Z\) is
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For identical strings, \(f = \frac{1}{2L}\sqrt{T/\mu}\) so \(f \propto \sqrt{T}\).
Updated On: Nov 5, 2026
- 2.25
- 0.44
- 1.25
- 1.5
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The Correct Option is A
Solution and Explanation
Fundamental frequency \(f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}\). The strings are identical (same \(L\) and \(\mu\)), so \(f \propto \sqrt{T}\).
\(\frac{T_X}{T_Z} = \left(\frac{f_X}{f_Z}\right)^2 = \left(\frac{450}{300}\right)^2 = (1.5)^2 = 2.25\).
Answer: (1) 2.25
\(\frac{T_X}{T_Z} = \left(\frac{f_X}{f_Z}\right)^2 = \left(\frac{450}{300}\right)^2 = (1.5)^2 = 2.25\).
Answer: (1) 2.25
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