Question:

Two fair dice are thrown. The probability that the sum of the scores is \(7\) such that the number on the second die is greater than that on the first die is ...

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List the pairs with sum 7 where the second number is larger and divide by 36.
Updated On: Nov 12, 2026
  • \(\frac{1}{6}\)
  • \(\frac{1}{12}\)
  • \(\frac{3}{4}\)
  • \(\frac{1}{36}\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
Two dice give 36 equally likely outcomes. Count the pairs (first, second) with sum 7 and second greater than first.

Step 2: List the favourable pairs
Sum 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1).
Second greater than first: (1,6), (2,5), (3,4).

Step 3: Count
There are 3 favourable outcomes out of 36.

Step 4: Probability
\(P=\frac{3}{36}=\frac{1}{12}\).

Final Answer:
The probability is 1/12. \[ \boxed{\text{(B) }\dfrac{1}{12}} \]
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