Two equal heavy spheres, each of radius r, are in equilibrium within a smooth cup of radius 3r. The ratio of reaction between the cup and one sphere and that between the two spheres is
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In symmetric contact problems, geometry decides force ratios.
Step 1: The centres of the spheres form an equilateral triangle with the centre of the cup.
Step 2: Angle between reaction forces is 60^∘.
Step 3: Resolving forces for equilibrium gives
fracRcupRₛphₑᵣₑ = 3