Question:

Two concentric conducting spherical shells A and B having radii rA and rB (rB > rA) are charged to QA and -QB (|QB| > |QA|). The electric field along a line passing through the centre is 

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For conducting shells: \beginitemize • Electric field inside conductor = 0 • Field depends on net enclosed charge • Sudden jump in E occurs at charged surfaces \enditemize
Updated On: Mar 19, 2026
  • As shown in graph (a)
  • As shown in graph (b)
  • As shown in graph (c)
  • As shown in graph (d)
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The Correct Option is C

Solution and Explanation

Step 1: Inside inner conducting shell: E = 0 (r < rA) 

Step 2: Between shells: E = (1)/(4πepsilon₀)(QA)/(r²) 

Step 3: Outside outer shell: E = (1)/(4πepsilon₀)((QA - QB))/(r²) Since |QB| > |QA|, field direction reverses. Thus graph (C) correctly represents variation of electric field.

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