Question:

Two coils, X and Y, are kept in close vicinity of each other. When a varying current, \(I(t)\), flows through coil X, the induced emf \((V(t))\) in coil Y, varies in the manner shown here.
The variation of \(I(t)\), with time, can then be represented by the graph labelled as graph :

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The induced emf is \(V = -M\frac{dI}{dt}\), so the slope of \(I(t)\) must be proportional to \(-V(t)\).
Updated On: Oct 31, 2026
  • (A)
  • (C)
  • (B)
  • (D)
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The Correct Option is B

Solution and Explanation

The emf induced in Y is \(V = -M\frac{dI}{dt}\), so \(\frac{dI}{dt} = -\frac VM\).
Interval 1 (V is a positive dome, zero at both ends): \(\frac{dI}{dt}\) is negative and zero at the start and at the end, so \(I\) decreases smoothly with a flat tangent at both ends of this interval.
Interval 2 (V is a constant negative value): \(\frac{dI}{dt}\) is a constant positive value, so \(I\) rises along a straight line.
Afterwards \(V = 0\): \(\frac{dI}{dt} = 0\), so \(I\) becomes constant.
Only graph (C) has these features: smooth decrease to a flat minimum, a straight rise, then a constant value. Graph (A) keeps rising indefinitely (it would need a constant emf forever) and has a vertical jump (infinite emf); (B) and (D) first increase, which needs a negative emf initially, and (D) also has a jump.
Answer: (2) C
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