Question:

Two coils 'P' and 'Q' are separated by some distance. When a current of 3 A flows through coil 'P', a magnetic flux of \(10^{-3}\) Wb passes through 'Q'. No current is passed through 'Q'. When no current passes through 'P' and a current of 2 A passes through 'Q', the flux through 'P' is :-

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Mutual inductance is reciprocal: \(M_{PQ}=M_{QP}\), with \(\Phi=MI\).
Updated On: Nov 5, 2026
  • \(3.67\times10^{-4}\) Wb
  • \(3.67\times10^{-3}\) Wb
  • \(6.67\times10^{-4}\) Wb
  • \(6.67\times10^{-3}\) Wb
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The Correct Option is C

Solution and Explanation

Mutual inductance from the first case: \(M=\frac{\Phi_Q}{I_P}=\frac{10^{-3}}{3}\ \mathrm{H}\approx3.33\times10^{-4}\) H.
By reciprocity the same \(M\) applies when current flows in Q: \(\Phi_P=M I_Q=\frac{10^{-3}}{3}\times2\approx6.67\times10^{-4}\) Wb.
Answer: (3) \(6.67\times10^{-4}\) Wb
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