Step 1: Understanding the Concept:
For a parallel plate capacitor, \(C = \frac{\varepsilon_0 A}{d}\). For circular plates, \(A = \pi r^2\).
Step 2: Key Formula or Approach:
New radius \(= \sqrt3\,r\), so the new area is \(\pi\cdot 3r^2 = 3A\). New separation \(= \frac d2\).
Step 3: Detailed Explanation:
\[ C_2 = \frac{\varepsilon_0 (3A)}{d/2} = 6\cdot\frac{\varepsilon_0 A}{d} = 6C_1 \]
So \(\frac{C_1}{C_2} = \frac16\), which is \(1 : 6\).
Option D, \(6:1\), is the inverse ratio.
Final Answer:
\(C_1 : C_2 = 1 : 6\), option (C).
\[ \boxed{1:6} \]