Question:

Two circular coils A and B are made from same wire but the radius of coil A is twice that of coil B. If the magnetic field at their centres is same then the ratio potential difference applied across them is

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Write the field at the centre in terms of the current and radius, use the resistance proportional to length to relate current to voltage, and equate the two fields.
Updated On: Nov 12, 2026
  • \(3:1\)
  • \(4:1\)
  • \(6:1\)
  • \(2:1\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
The field at the centre of a circular coil is \(B=\frac{\mu_{0}I}{2r}\). The resistance of the same wire is proportional to its length, so \(R\propto r\).

Step 2: Current in Terms of Voltage
\(I=\frac{V}{R}\propto\frac{V}{r}\), so \(B\propto\frac{V}{r\cdot r}=\frac{V}{r^{2}}\).

Step 3: Equal Fields
\(\frac{V_{A}}{r_{A}^{2}}=\frac{V_{B}}{r_{B}^{2}}\).

Step 4: Calculation
\(\frac{V_{A}}{V_{B}}=\left(\frac{r_{A}}{r_{B}}\right)^{2}=2^{2}=4\).

Final Answer:
The potential differences are in the ratio 4 to 1. \[ \boxed{\text{(B) }4:1} \]
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