Two charges, each \( +q \), are placed at the corners of an isosceles triangle ABC of sides BC and AC, 2a. D and E are the mid-points of BC and CA. The work done in taking a charge \( Q \) from D to E is
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In a system with symmetry, if the points of movement are equidistant from the charges, no work is required.
Since points D and E are equidistant from the charges, the potential at these points is the same, meaning no work is done in moving the charge from D to E.
Step 2: Conclusion.
The work done is zero, corresponding to option (c).