Step 1: Use the potentiometer principle.
In a potentiometer, the emf of a cell is directly proportional to the balancing length.
Therefore,
\[
\frac{E_A}{E_B}=\frac{l_A}{l_B}.
\]
Step 2: Substitute the given values.
Given,
\[
E_A=2.4\ \text{V},
\]
\[
l_A=360\ \text{cm},
\]
and
\[
l_B=420\ \text{cm}.
\]
Thus,
\[
\frac{2.4}{E_B}=\frac{360}{420}.
\]
Step 3: Solve for \(E_B\).
\[
E_B=2.4\times \frac{420}{360}.
\]
\[
E_B=2.4\times \frac{7}{6}.
\]
\[
E_B=2.8\ \text{V}.
\]
Step 4: Final conclusion.
Therefore, the emf of the second cell \(B\) is
\[
\boxed{2.8\ \text{V}}
\]
Hence, the correct option is
\[
\boxed{(1)}
\]