Two blocks are connected over a massless pulley as shown in figure. The mass of block A is 10 kg and the coefficient of kinetic friction is 0.2. Block A slides down the incline at constant speed. The mass of block B in kg is:
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Constant speed motion implies net force equals zero.
Step 1: Since block A moves with constant speed, net force on it is zero.
Step 2: Along the incline:
mg\sin30^ - μ mg\cos30^ - T = 0
Step 3: For block B:
T = mB g
Step 4: Solving gives
mB ≈ 3.3 kg