Question

To obtain the given truth table, the following logic gate should be placed at G:

• A. AND Gate
• B. OR Gate
• C. NOR Gate
• D. NAND Gate

Hint:

For analyzing logic circuits: - Start by identifying the effect of NOT, AND, and OR gates on the inputs. - Derive the Boolean expression for the final output. - Compare the derived expression with standard logic gate outputs to determine the correct gate.

Answer 1

The Correct Option is C

Step 1: Analyze the circuit structure. - The given circuit consists of two NOT gates applied to \( A \) and \( B \), followed by two AND gates whose outputs feed into gate \( G \). - The final truth table indicates that \( Y \) is high for \( (A, B) = (0,0) \) and \( (1,1) \), but low otherwise. Step 2: Identify the logical expression. Observing the output pattern, we recognize it corresponds to the NOR operation: \[ Y = \overline{A + B}. \] Step 3: Select the appropriate gate. - The only logic gate that produces \( Y = \overline{A + B} \) is the NOR Gate. - Thus, the correct choice for gate \( G \) is a NOR gate. Thus, the answer is \( \boxed{\text{NOR Gate}} \).

Answer 2

Step 1: Recall the behavior of the NOR gate. 

A NOR gate gives output \(1\) only when all inputs are \(0\). Otherwise, the output is \(0\).

Step 2: Truth table for the NOR gate.

Input A	Input B	Output (A NOR B)
0	0	1
0	1	0
1	0	0
1	1	0

This matches the truth table given in the question — output is high (1) only when both inputs are low (0).

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Final Answer:

\[ \boxed{\text{NOR Gate}} \]