
Step 1: Analyze the circuit structure. - The given circuit consists of two NOT gates applied to \( A \) and \( B \), followed by two AND gates whose outputs feed into gate \( G \). - The final truth table indicates that \( Y \) is high for \( (A, B) = (0,0) \) and \( (1,1) \), but low otherwise.
Step 2: Identify the logical expression. Observing the output pattern, we recognize it corresponds to the NOR operation: \[ Y = \overline{A + B}. \]
Step 3: Select the appropriate gate. - The only logic gate that produces \( Y = \overline{A + B} \) is the NOR Gate.
- Thus, the correct choice for gate \( G \) is a NOR gate. Thus, the answer is \( \boxed{\text{NOR Gate}} \).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


Draw truth table of given gate circuit.


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)