Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also, name the triangle formed by the forces as sides
Show Hint
- $60^{\circ}$ equilateral triangle
- $120^{\circ}$ equilateral triangle
- $120^{\circ}$ $30^{\circ}$ $30^{\circ}$ an isosceles triangle
- $120^{\circ}$ an obtuse triangle
The Correct Option is B
Solution and Explanation
For three forces to be in equilibrium, they must form a closed triangle when represented as vectors.
Step 2: Detailed Explanation:
For three forces of equal magnitude to be in equilibrium, they must be at $120^{\circ}$ to each other. When these forces are represented as sides of a triangle, they form an equilateral triangle.
Step 3: Final Answer:
The angle is $120^{\circ}$ and the triangle is equilateral.
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