Question:
This question has Statement-1 and Statement-2. Of the four choices given after the Statements, choose the one that best describes the two Statements.
Statement-1 : Out of radio waves and microwaves, the radio waves undergo more diffraction.
Statement-2 : Radio waves have greater frequency compared to microwaves.
This question has Statement-1 and Statement-2. Of the four choices given after the Statements, choose the one that best describes the two Statements.
Statement-1 : Out of radio waves and microwaves, the radio waves undergo more diffraction.
Statement-2 : Radio waves have greater frequency compared to microwaves.
Statement-1 : Out of radio waves and microwaves, the radio waves undergo more diffraction.
Statement-2 : Radio waves have greater frequency compared to microwaves.
Show Hint
Compare the wavelengths of radio waves and microwaves; diffraction is larger for longer wavelength.
Updated On: Nov 4, 2026
- Statement-1 is true, Statement-2 is true and Statement-2 is the correct explanation of Statement-1
- Statement-1 is false, Statement-2 is true.
- Statement-1 is true, Statement-2 is false.
- Statement-1 is true, Statement-2 is true but Statement-2 is not the correct explanation of Statement-1
Show Solution
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The Correct Option is C
Solution and Explanation
In the electromagnetic spectrum, radio waves have wavelengths longer than about 1 mm up to several km, while microwaves lie roughly between 1 mm and 30 cm.
So radio waves have the longer wavelength and the lower frequency.
Diffraction around an obstacle or aperture of size a is appreciable when \(\lambda \gtrsim a\), so longer wavelength means more diffraction. Hence Statement-1 is true.
Since \(f = c/\lambda\), radio waves have a smaller frequency than microwaves. Hence Statement-2 is false.
Answer: (3) Statement-1 is true, Statement-2 is false.
So radio waves have the longer wavelength and the lower frequency.
Diffraction around an obstacle or aperture of size a is appreciable when \(\lambda \gtrsim a\), so longer wavelength means more diffraction. Hence Statement-1 is true.
Since \(f = c/\lambda\), radio waves have a smaller frequency than microwaves. Hence Statement-2 is false.
Answer: (3) Statement-1 is true, Statement-2 is false.
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