Question:
This question has Statement-1 and Statement-2. Of the four choices given after the Statements, choose the one that best describes the two Statements.
Statement-1: A capillary is dipped in a liquid and liquid rises to a height \(h\) in it. As the temperature of the liquid is raised, the height \(h\) increases (if the density of the liquid and the angle of contact remain the same).
Statement-2: Surface tension of a liquid decreases with the rise in its temperature.
This question has Statement-1 and Statement-2. Of the four choices given after the Statements, choose the one that best describes the two Statements.
Statement-1: A capillary is dipped in a liquid and liquid rises to a height \(h\) in it. As the temperature of the liquid is raised, the height \(h\) increases (if the density of the liquid and the angle of contact remain the same).
Statement-2: Surface tension of a liquid decreases with the rise in its temperature.
Statement-1: A capillary is dipped in a liquid and liquid rises to a height \(h\) in it. As the temperature of the liquid is raised, the height \(h\) increases (if the density of the liquid and the angle of contact remain the same).
Statement-2: Surface tension of a liquid decreases with the rise in its temperature.
Show Hint
Use \(h = \frac{2T\cos\theta}{r\rho g}\) and recall how surface tension changes with temperature.
Updated On: Oct 31, 2026
- Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation for Statement-1.
- Statement-1 is false, Statement-2 is true.
- Statement-1 is true, Statement-2 is false.
- Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation for Statement-1.
Show Solution
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The Correct Option is B
Solution and Explanation
Capillary rise: \(h = \frac{2T\cos\theta}{r\rho g}\).
Statement-2 is true: surface tension of a liquid decreases as temperature rises (it vanishes at the critical temperature).
With \(\rho\), \(\theta\) and \(r\) unchanged, \(h \propto T\), so when the temperature rises and \(T\) decreases, \(h\) decreases, not increases. Hence Statement-1 is false.
Statement-1 false, Statement-2 true.
Answer: (2) Statement-1 is false, Statement-2 is true.
Statement-2 is true: surface tension of a liquid decreases as temperature rises (it vanishes at the critical temperature).
With \(\rho\), \(\theta\) and \(r\) unchanged, \(h \propto T\), so when the temperature rises and \(T\) decreases, \(h\) decreases, not increases. Hence Statement-1 is false.
Statement-1 false, Statement-2 true.
Answer: (2) Statement-1 is false, Statement-2 is true.
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