Step 1: Count the odd places
In a row of \(8\) seats the odd places are \(1,3,5,7\). So there are \(4\) odd places.
Step 2: Place the girls
The \(3\) girls choose \(3\) of these \(4\) places in order: \({}^4P_3=4\times3\times2=24\) ways.
Step 3: Place the boys
The \(5\) boys fill the remaining \(5\) seats in \(5!=120\) ways.
Step 4: Multiply
\[ 24\times120=2880 \]
Final Answer:
The number of arrangements is \(2880\), option (B).
\[ \boxed{\text{(B) }2880} \]