Question

The work function of a material that has the threshold frequency of \(5 \times 10^{14} \, Hz\) is (\(h = 6.626 \times 10^{-34}\) Js).

• A. 3.09eV
• B. 5.35eV
• C. 4.14eV
• D. 2.07 eV
• E. 1.03eV

Hint:

$1 \text{ eV} = 1.6 \times 10^{-19} \text{ Joules}$.

Answer 1

The Correct Option is D

Step 1: Concept
Work function ($\phi$) = $h \nu_0$, where $\nu_0$ is the threshold frequency.

Step 2: Meaning
$\phi = (6.626 \times 10^{-34}) \times (5 \times 10^{14}) \text{ Joules}$.

Step 3: Analysis
To convert Joules to eV, divide by $1.6 \times 10^{-19}$:
$\phi = \frac{6.626 \times 10^{-34} \times 5 \times 10^{14}}{1.6 \times 10^{-19}} = \frac{33.13 \times 10^{-20}}{1.6 \times 10^{-19}} \approx 2.07 \text{ eV}$.

Step 4: Conclusion
Hence, the work function is 2.07 eV.
Final Answer: (D)