In an adiabatic process, an ideal gas changes without exchanging heat with the surroundings. The work done in such a process can be understood by looking at the equation for an adiabatic process:
PVγ = constant,
where P is the pressure, V is the volume, and γ (gamma) is the adiabatic index or specific heat ratio (Cp/Cv).
The work done (W) in an adiabatic process can be expressed by the relation:
W = (P1V1 - P2V2) / (γ - 1).
Using the adiabatic condition, one can also express the work done in terms of the change in volume:
The relation simplifies to:
W = (Cv(T1 - T2))/(1-γ)
However, directly relating work done to volume change:
W = ((P1V1 - P2V2))/(γ - 1)) = K(V21-γ - V11-γ)/(1-γ)
Thus, it is clear that the work done depends directly on the volume of the gas during the adiabatic change. Therefore, the correct choice regarding what the work done depends upon in an adiabatic change is: change in its volume.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,




What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)